document.write( "Question 568898: Skyler is 20 years older than Jason. In 8 years, Skyler will be twice as old as Jason. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #367173 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Present age of Skyler = s
\n" ); document.write( "Present age of Jason = j\r
\n" ); document.write( "\n" ); document.write( "Given
\n" ); document.write( "Skyler is 20 years older than Jason
\n" ); document.write( "s=j+20.................(1)
\n" ); document.write( "In 8 years
\n" ); document.write( "Skyler will be = s+8
\n" ); document.write( "Jason will be = j+8
\n" ); document.write( "Then
\n" ); document.write( "Skyler will be twice as old as Jason
\n" ); document.write( "s+8=2(j+8)
\n" ); document.write( "s+8=2j+16
\n" ); document.write( "s=2j+16-8
\n" ); document.write( "s=2j+8..............(2)
\n" ); document.write( "Put the value of s from (1) to (2)\r
\n" ); document.write( "\n" ); document.write( "j+20=2j+8
\n" ); document.write( "j-2j=8-20
\n" ); document.write( "-j=-12
\n" ); document.write( "Multiply by -1 both sides
\n" ); document.write( "(-1)(-j)=(-1)(-12)
\n" ); document.write( "j=12\r
\n" ); document.write( "\n" ); document.write( "Put the value of j in (1)
\n" ); document.write( "s=j+20
\n" ); document.write( "s=12+20
\n" ); document.write( "s=32\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Present age of Skyler = s = 32 years old
\n" ); document.write( "Present age of Jason = j = 12 years old
\n" ); document.write( " \n" ); document.write( "
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