document.write( "Question 568850: How many ounces of a solution that is 90% alcohol need to be mixed with 5 ounces of a solution that is 50% alcohol in order to obtain a solution that is 80% alcohol?\r
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document.write( "I have tried a formula: 5(.50) + x(.90) = .80, but the answer yields a negative amount of ounces which is not possible. \n" );
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Algebra.Com's Answer #367150 by josmiceli(19441) You can put this solution on YOUR website! Let \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "given: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "15 ounces of 90% solution are needed \n" ); document.write( "check answer: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " |