document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=568387>Question 568387</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Prove that if in a cyclic quadrilateral, one pair of opposite angles is congruent, then the other pair of opposite sides is parallel </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #367040 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=367040\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I don't think that statement is true. If one pair of opposite angles in a cyclic quadrilateral is congruent, then both angles must be 90 (since opposite angles in a cyclic quadrilateral add up to 180, 180/2 = 90). It is definitely possible to construct a cyclic quadrilateral satisfying that property without any parallel sides.\r<BR>\n" );
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document.write( "Not completely drawn well, but you get the picture. If angles A and C are congruent in cyclic quadrilateral ABCD, then A and C are right angles. There are no parallel sides. </SPAN>\n" );
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