document.write( "Question 568540: write an equation that describes the line that passes through [-3,1] and is parallel to the line described by y= 4x + 1 ? \n" ); document.write( "
Algebra.Com's Answer #367030 by nyc_function(2741)\"\" \"About 
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The line we want will need to have the same slope as the given line.\r
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\n" ); document.write( "\n" ); document.write( "The slope of the given line is the coefficient of x.\r
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\n" ); document.write( "\n" ); document.write( "What is the slope?\r
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\n" ); document.write( "\n" ); document.write( "The slope is 4. Do you see it in your equation?\r
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\n" ); document.write( "\n" ); document.write( "We now use the point-slope formula y - y1 = m(x - x1).\r
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\n" ); document.write( "\n" ); document.write( "NOTE: y1 is read \"y sub 1\" and x1 is read \"x sub one\".\r
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\n" ); document.write( "\n" ); document.write( "We plug the given point and slope into the formula to find a line parallel to the given line.\r
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\n" ); document.write( "\n" ); document.write( "Let y1 = 1\r
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\n" ); document.write( "\n" ); document.write( "Let x1 = -3\r
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\n" ); document.write( "\n" ); document.write( "Let m = slope = 4\r
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\n" ); document.write( "\n" ); document.write( "We now plug and chug.\r
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\n" ); document.write( "\n" ); document.write( "y - 1 = 4(x -(-3))\r
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\n" ); document.write( "\n" ); document.write( "y - 1 = 4(x + 3)\r
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\n" ); document.write( "\n" ); document.write( "y - 1 = 4x + 12\r
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\n" ); document.write( "\n" ); document.write( "y = 4x + 12 + 1\r
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\n" ); document.write( "\n" ); document.write( "y = 4x + 13\r
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\n" ); document.write( "\n" ); document.write( "Did you follow?
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