document.write( "Question 54436: I need help. Solve the following system by using either addition or substitution. If a unique solution does not exist, state whether the system is dependent or inconsistent.
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document.write( "10x + 2y = 7 and y = -5x + 3
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Algebra.Com's Answer #36700 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! SEE THE FOLLOWING EXAMPLES AND TRY IF STILL IN DIFFICULTY PLEASE COME BACK \n" ); document.write( "-------------------------------------------------------------------------- \n" ); document.write( "Solve the following system by addition. If a unique \n" ); document.write( "solution does not exist, state \n" ); document.write( "whether the system is inconsistent or dependent. \n" ); document.write( "x + 5y =10...........................................I \n" ); document.write( "-2x - 10y = -20.................................II \n" ); document.write( "-2*EQN.I GIVES \n" ); document.write( "-2X-10Y=-20....WHICH IS SAME AS EQN.II... \n" ); document.write( "HENCE THEY ARE DEPENDENT EQUATIONS. \n" ); document.write( "SO INEFFECT WE HAVE ONLY ONE EQN.TO SOLVE FOR 2 \n" ); document.write( "UNKOWNS. \n" ); document.write( "HENCE WE SHALL HAVE INFINTE SOLUTIONS LIKE IN THIS \n" ); document.write( "CASE \n" ); document.write( "X=0....Y=2 \n" ); document.write( "X=10...Y=0...ETC.. \n" ); document.write( "IMPORTANT NOTE. \n" ); document.write( "THEY HAVE INFINITE SOLUTIONS BUT NOT ANY AND EVERY \n" ); document.write( "VALUE OF X AND Y.FOR EXAMPLE IF X=0 ,THEN Y HAS TO \n" ); document.write( "EQUAL 2 ONLY NOT ANY OTHER VALUE.SO IT HAS INFINITE \n" ); document.write( "SETS OF X AND Y PAIRS FOR ITS SOLUTION \n" ); document.write( "ANOTHER EXAMPLE IS \n" ); document.write( "X+Y=1........................1 \n" ); document.write( "2X+2Y=2..............................2 \n" ); document.write( "HERE AGIN EQN.2IS JUST A MULTIPLICATION OF EQN.1 WITH 2 ON BOTH LHS AND RHS \n" ); document.write( "THE GERAL SOLUTION FORMULA IS Y=1-X...OR (X,1-X)IS A \n" ); document.write( "SOLUTION SET..LIKE (1,0),(2,-1) ETC.... \n" ); document.write( "THUS DEPENDENT EQNS.HAVE LHS AND RHS IN THE SAME PRPORTION OR COMBINATION IN DIFFERENT EQNS. \n" ); document.write( "---------------------------------------------------------------------------- \n" ); document.write( "AS THE NAME IMPLIES AN INCONSISTENT SET OF EQUATIONS \n" ); document.write( "HAS NO SOLUTION AS THEY ARE INCONSISTENT.FOR EXAMPLE \n" ); document.write( "X+Y=2.....................1 \n" ); document.write( "2X+2Y=3.....................2 \n" ); document.write( "IF WE TRY TO SATISFY EQN.1,WE CANT SATISFY EQN.2 AND VICEVERSA...AS THE LHS OF BOTH EQNS.ARE INPROPORTION OF 1:2,WHERE AS RHS IS IN THE RATIO OF 2:3 \n" ); document.write( "HENCE THERE IS NO QUESTION OF GETTING A \n" ); document.write( "GENERAL SOLUTION FOR THAT BY ANY METHOD . \n" ); document.write( "SO INCONSISTENT EQNS HAVE LHS AS MULTIPLES OR COMBINATIONS IN ONE PROPORTION WHILE RHS IS IN DIFFERENT PROPORTION IN DIFFERENT EQNS. \n" ); document.write( "-------------------------------------------------------------------- \n" ); document.write( "FINALLY CONSISTENT AND INDEPENDENT EQNS.HAVE UNIQUE \n" ); document.write( "SOLUTION..FOR EXAMPLE \n" ); document.write( "X+Y=2...................1 \n" ); document.write( "X-Y=0..........................2 \n" ); document.write( "EQN.1 +EQN.2 GIVES \n" ); document.write( "2X=2...OR...X=1 \n" ); document.write( "SUBSTITUTING IN EQN.1 ,WE GET Y=1.THUS THEY \n" ); document.write( "HAVE ONE UNIQUE SOLUTION X=1 AND Y=1 \n" ); document.write( "HERE LHS OF DIFFERENT EQNS.IS NOT A DIRECT MULTIPLE OR COMBINATIONS OF OTHER EQNS. \n" ); document.write( "------------------------------------------------------------------------- \n" ); document.write( " \n" ); document.write( " |