document.write( "Question 568305: A rectangle has a width of 3X inches and a length that is 8 inches shorter. The area is 825 sq. inches find the dimensions.
\n" ); document.write( "X_____, W__________,L____________, Perimeter________ \n" ); document.write( "
Algebra.Com's Answer #366908 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Width = 3x
\n" ); document.write( "Length = 3x-8
\n" ); document.write( "Area = L*W\r
\n" ); document.write( "\n" ); document.write( "825 = 3x(3x-8)\r
\n" ); document.write( "\n" ); document.write( "825=9x^2-24x\r
\n" ); document.write( "\n" ); document.write( "9x^2-24x-825=0\r
\n" ); document.write( "\n" ); document.write( "Find the roots of the equation by quadratic formula
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\n" ); document.write( "a= 9 , b= -24 , c= -825
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\n" ); document.write( "b^2-4ac= 576 + 29700
\n" ); document.write( "b^2-4ac= 30276 \"%09sqrt%28%0930276%09%29=%09174%09\"
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x1=( 24 + 174 )/ 18
\n" ); document.write( "x1= 11.00
\n" ); document.write( "x2=( 24 -174 ) / 18
\n" ); document.write( "x2= -8.33
\n" ); document.write( "Ignore negative value
\n" ); document.write( "x = 11 \r
\n" ); document.write( "\n" ); document.write( "width = 3x = 33 inches
\n" ); document.write( "Length = 3x-8 , 33-8=25 inches\r
\n" ); document.write( "\n" ); document.write( "Perimeter = 2(L+W)\r
\n" ); document.write( "\n" ); document.write( "you can work that out\r
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\n" ); document.write( "\n" ); document.write( "CHECK\r
\n" ); document.write( "\n" ); document.write( "33 * 25 = 825\r
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\n" ); document.write( "m.ananth@hotmail.ca
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