document.write( "Question 54439: 9x+14=41\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "3x-4=11 \n" );
document.write( "
Algebra.Com's Answer #36690 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! We need to get x all by itself on one side of the = sign within the rules of algebra. Whatever you do to one side of the equal sign, you have to do to the other. \n" ); document.write( "9x+14=41 (14 doesn't have an x, so we need to move it. It's being added, so subtract it from both sides of the equal sign.) \n" ); document.write( "9x+14-14=41-14 \n" ); document.write( "9x+0=27 \n" ); document.write( "9x=27 (x is being multiplied by 9, so we divide 9 on both sides. \n" ); document.write( "9x/9=27/9 \n" ); document.write( "1x=3 \n" ); document.write( " \n" ); document.write( "Check by substituting x=3 back into the original equation to see if both sides equal. \n" ); document.write( "9(3)+14=41 \n" ); document.write( "27+14=41 \n" ); document.write( "41=41 We're right!!!! \n" ); document.write( ": \n" ); document.write( "3x-4=11 (4 doesn't have an x so we add it to both sides of the equal sign.) \n" ); document.write( "3x-4+4=11+4 \n" ); document.write( "3x+0=15 \n" ); document.write( "3x=15 (x is being multiplied by 3, so divide both sides of the equation by 3.) \n" ); document.write( "3x/3=15/3 \n" ); document.write( "1x=5 \n" ); document.write( " \n" ); document.write( "Check you answer by substituting x=5 into the original equation and see if both sides equal. \n" ); document.write( "3(5)-4=11 \n" ); document.write( "15-4=11 \n" ); document.write( "11=11 Right again!!! \n" ); document.write( "Happy Calculating!!! \n" ); document.write( " |