document.write( "Question 568185: flying with the wind, a jet can travel the 4200 km distaance between san francisco and new work in 6 hour. the return trip against the wind takes 7 hours. find the rate of the jet in still air and the rate of the wind \n" ); document.write( "

Algebra.Com's Answer #366857 by mananth(16946) $\"\"$ $\"About$

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plane speed=x mph
\n" ); document.write( "wind speed=y mph
\n" ); document.write( "with wind Speed = (x+y)
\n" ); document.write( "against wind speed= (x-y)
\n" ); document.write( "d= 4200
\n" ); document.write( "4200 / (x+y= 6
\n" ); document.write( "divide by 6
\n" ); document.write( "700 / (x+y)= 1
\n" ); document.write( "x+ y 700 ............1
\n" ); document.write( "d= 4200
\n" ); document.write( "4200 /(x-y)= 7
\n" ); document.write( "divide by 7
\n" ); document.write( "600 /(x-y) = 7
\n" ); document.write( " x-y = 600.00 .............2
\n" ); document.write( "add up (1) & (2)
\n" ); document.write( "2 x = 1300
\n" ); document.write( "/ 2
\n" ); document.write( "x= 650 mph speed of plane in still air
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "we get y= 50 mph speed of wind
\n" ); document.write( " \n" ); document.write( "

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