document.write( "Question 568107: It is my 2nd day in my geometry class, I have switched from an online school & I have an upcoming test on slope/midpoint/distance. Im stuck on a question from the study guide because I was not there for the lessons. I need help ASAP!\r
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\n" ); document.write( "The length of a rectangle is three times as long as it is wide. If the length of the diagonal is 10sqrt6 feet, find the area of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "I cannot solve for this question no matter what I try!
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Algebra.Com's Answer #366853 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
if x is the width, then 3x is the length\r
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\n" ); document.write( "\n" ); document.write( "by Pythagoras ___ x^2 + (3x)^2 = [10sqrt(6)]^2 ___ x^2 + 9x^2 = 10^2 * [sqrt(6)]^2\r
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\n" ); document.write( "\n" ); document.write( "10x^2 = 600 ___ x^2 = 60\r
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\n" ); document.write( "\n" ); document.write( "the area is ___ x * 3x ___ or 3x^2\r
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\n" ); document.write( "\n" ); document.write( "3(60) = 180
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