document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=568018>Question 568018</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the fraction in terms of the LCM of the denominators.\r<BR>\n" );
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document.write( "9 over (x-1)^2 , 6 over x(x-1)\r<BR>\n" );
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document.write( "I thought I was supposed to find the LCD. How do you solve this?<BR>\n" );
document.write( "I know the answer is 9x over x(x-1)^2 , 6x-6 over x(x-1)^2<BR>\n" );
document.write( "but I don't understand how to get to that. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #366833 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=366833\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Write the fraction in terms of the LCM of the denominators. <BR>\n" );
document.write( "9 over (x-1)^2 , 6 over x(x-1) <BR>\n" );
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document.write( "LCM = x(x-1)^2<BR>\n" );
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document.write( "Rewrite each fraction with the LCM as its denominator<BR>\n" );
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document.write( "[9/(x-1)^2] = [9x/LCM]<BR>\n" );
document.write( "----<BR>\n" );
document.write( "[6/(x(x-1))] = [6(x+1)/LCM]<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "----<BR>\n" );
document.write( " </SPAN>\n" );
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