document.write( "Question 567914: The vertex angle of an isosceles triangle is 72°,and each of equal sides is 10 cm.Find the perimeter and the area of of the triangle. \n" ); document.write( "
Algebra.Com's Answer #366800 by mananth(16946)\"\" \"About 
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let the vertex be A where the legs meet\r
\n" ); document.write( "\n" ); document.write( "legs are 10 cm each
\n" ); document.write( "B & C are the vertices of the base\r
\n" ); document.write( "\n" ); document.write( "Law of Sines\r
\n" ); document.write( "\n" ); document.write( "a/sin A = b/sin B = c/sin C\r
\n" ); document.write( "\n" ); document.write( "a/sin 72 = 10/Sin 54 = c/Sin 54\r
\n" ); document.write( "\n" ); document.write( "a= 10*sin 72/Sin 54
\n" ); document.write( "a= 11.75\r
\n" ); document.write( "\n" ); document.write( "So the perimeter = 11.75+10+10
\n" ); document.write( "perimeter = 31.75 cm
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