document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=567922>Question 567922</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two years ago, Anton was three times as old as his sister, Nathalie. In 4 years, he will be only twice his sister's age. Find their present ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #366797 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=366797\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2 years gao Nathalie ---x years<BR>\n" );
document.write( "Anton 3x\r<BR>\n" );
document.write( "\n" );
document.write( "After 4 years<BR>\n" );
document.write( "Nathalie  will be x+6<BR>\n" );
document.write( "Anton 3x+6\r<BR>\n" );
document.write( "\n" );
document.write( "3x+6 =2(x+6)\r<BR>\n" );
document.write( "\n" );
document.write( "3x+6 =2x+12<BR>\n" );
document.write( "3x-2x=12-6<BR>\n" );
document.write( "x=6\r<BR>\n" );
document.write( "\n" );
document.write( "2 years ago Nathalie was 6 years<BR>\n" );
document.write( "now she is 8 years<BR>\n" );
document.write( "Anton was 3x years = 3*6 = 18.<BR>\n" );
document.write( "so he wil be 20 years now </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );