document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=567908>Question 567908</A>: <I><SPAN STYLE=\"word-break: break-all;\"> It is necessary to have a 40% solution in the radiator of a certain car.  The radiator now has 50 liters of 20% solution.  How many liters of this should be drained and replaced with 100% antifreeze to get the desired strength?\r<BR>\n" );
document.write( "\n" );
document.write( "My answer = 20 liters\r<BR>\n" );
document.write( "\n" );
document.write( "Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #366792 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=366792\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It is necessary to have a 40% solution in the radiator of a certain car. The radiator now has 50 liters of 20% solution. How many liters of this should be drained and replaced with 100% antifreeze to get the desired strength? <BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let x = liters to be drained and replaced w/100% antifreeze<BR>\n" );
document.write( "then<BR>\n" );
document.write( ".20(50-x) + x = .40(50)<BR>\n" );
document.write( "10-.20x + x = 20<BR>\n" );
document.write( "10 + .80x = 20<BR>\n" );
document.write( ".80x = 10<BR>\n" );
document.write( "x = 10/.80<BR>\n" );
document.write( "x = 12.5 liters\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );