document.write( "Question 567717: solve the following equation for x: 27^(5-x) = 9^(x-2) \n" ); document.write( "
Algebra.Com's Answer #366773 by jim_thompson5910(35256)\"\" \"About 
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27^(5-x) = 9^(x-2)\r
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\n" ); document.write( "\n" ); document.write( "(3^3)^(5-x) = (3^2)^(x-2)\r
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\n" ); document.write( "\n" ); document.write( "3^(3(5-x)) = 3^(2(x-2))\r
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\n" ); document.write( "\n" ); document.write( "Since the bases are equal, the exponents are equal.\r
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\n" ); document.write( "\n" ); document.write( "3(5-x)=2(x-2)\r
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\n" ); document.write( "\n" ); document.write( "15-3x=2x-4\r
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\n" ); document.write( "\n" ); document.write( "-3x=2x-4-15\r
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\n" ); document.write( "\n" ); document.write( "-3x-2x=-4-15\r
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\n" ); document.write( "\n" ); document.write( "-5x=-4-15\r
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\n" ); document.write( "\n" ); document.write( "-5x=-19\r
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\n" ); document.write( "\n" ); document.write( "x=(-19)/(-5)\r
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\n" ); document.write( "\n" ); document.write( "x=19/5
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