document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=567726>Question 567726</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a 60 degree sector of a circle is 36pi cm^2. What is the diameter of the circle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #366679 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=366679\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area of a 60 degree sector of a circle is 36pi cm^2. What is the diameter of the circle?<BR>\n" );
document.write( "That sector has 1/4 of the total area of the circle.<BR>\n" );
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document.write( "Area of the circle = 4(36pi) = 144pi<BR>\n" );
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document.write( "Area = (pi)r^2<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "(pi)r^2 = 144pi<BR>\n" );
document.write( "r^2 = 144<BR>\n" );
document.write( "r = 12<BR>\n" );
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document.write( "Diameter = 2r = 24 cm<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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