document.write( "Question 567656: marilyn is three years younger than her friend rosie. in seven years the product of their ages will be 2 less than six times the product of their ages five years ago. how ald are each at present \n" ); document.write( "
Algebra.Com's Answer #366662 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Present age of Marilyn = m
\n" ); document.write( "Present age of Rosie = r\r
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\n" ); document.write( "\n" ); document.write( "Marilyn is three years younger than her friend Rosie
\n" ); document.write( "m=r-3..............(1)\r
\n" ); document.write( "\n" ); document.write( "Five years ago
\n" ); document.write( "Age of Marilyn was = m-5
\n" ); document.write( "Age of Rosie was = r-5\r
\n" ); document.write( "\n" ); document.write( "In seven years
\n" ); document.write( "Age of Marilyn will be = m+7
\n" ); document.write( "Age of Rosie will be = r+7\r
\n" ); document.write( "\n" ); document.write( "THEN\r
\n" ); document.write( "\n" ); document.write( "In seven years the product of their ages will be 2 less than six times the product of their ages five years ago.\r
\n" ); document.write( "\n" ); document.write( "(m+7)(r+7)=6[(m-5)(r-5)]-2
\n" ); document.write( "mr+7m+7r+49=6(mr-5m-5r+25)-2
\n" ); document.write( "mr+7m+7r+49=6mr-30m-30r+150-2
\n" ); document.write( "mr-6mr+7m+30m+30r+7r=150-2-49
\n" ); document.write( "-5mr+37m+37r=150-51
\n" ); document.write( "-5mr+37m+37r=99..................(2)\r
\n" ); document.write( "\n" ); document.write( "Put the value of m from (1) to (2)
\n" ); document.write( "-5(r-3)r+37(r-3)+37r=99
\n" ); document.write( "-5r^2+15r+37r-111+37r=99
\n" ); document.write( "-5r^2+89r-99-111=0
\n" ); document.write( "-5r^2+89r-200=0
\n" ); document.write( "Now solve for r
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ar%5E2%2Bbr%2Bc=0\" (in our case \"-5r%5E2%2B89r%2B-210+=+0\") has the following solutons:
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\n" ); document.write( " \"r%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2889%29%5E2-4%2A-5%2A-210=3721\".
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\n" ); document.write( " Discriminant d=3721 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-89%2B-sqrt%28+3721+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"r%5B1%5D+=+%28-%2889%29%2Bsqrt%28+3721+%29%29%2F2%5C-5+=+2.8\"
\n" ); document.write( " \"r%5B2%5D+=+%28-%2889%29-sqrt%28+3721+%29%29%2F2%5C-5+=+15\"
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\n" ); document.write( " Quadratic expression \"-5r%5E2%2B89r%2B-210\" can be factored:
\n" ); document.write( " \"-5r%5E2%2B89r%2B-210+=+-5%28r-2.8%29%2A%28r-15%29\"
\n" ); document.write( " Again, the answer is: 2.8, 15.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+-5%2Ax%5E2%2B89%2Ax%2B-210+%29\"

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\n" ); document.write( "\n" ); document.write( "r=15 or r = 2.8 (reject)\r
\n" ); document.write( "\n" ); document.write( "Put r=15 in (1)
\n" ); document.write( "m=r-3
\n" ); document.write( "m=15-3
\n" ); document.write( "m=12\r
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\n" ); document.write( "\n" ); document.write( "Present age of Marilyn = m = 12 years old
\n" ); document.write( "Present age of Rosie = r = 15 years old\r
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\n" ); document.write( "\n" ); document.write( "Check
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\n" ); document.write( "Five years ago
\n" ); document.write( "Age of Marilyn was = 7
\n" ); document.write( "Age of Rosie was = 10\r
\n" ); document.write( "\n" ); document.write( "In seven years
\n" ); document.write( "Age of Marilyn will be = 19
\n" ); document.write( "Age of Rosie will be = 22\r
\n" ); document.write( "\n" ); document.write( "THEN\r
\n" ); document.write( "\n" ); document.write( "In seven years the product of their ages will be 2 less than six times the product of their ages five years ago.\r
\n" ); document.write( "\n" ); document.write( "19*22=6(7*10)-2
\n" ); document.write( "418=6(70)-2
\n" ); document.write( "418=420-2
\n" ); document.write( "418=418\r
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