document.write( "Question 567656: marilyn is three years younger than her friend rosie. in seven years the product of their ages will be 2 less than six times the product of their ages five years ago. how ald are each at present \n" ); document.write( "
Algebra.Com's Answer #366662 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "Present age of Marilyn = m \n" ); document.write( "Present age of Rosie = r\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Marilyn is three years younger than her friend Rosie \n" ); document.write( "m=r-3..............(1)\r \n" ); document.write( "\n" ); document.write( "Five years ago \n" ); document.write( "Age of Marilyn was = m-5 \n" ); document.write( "Age of Rosie was = r-5\r \n" ); document.write( "\n" ); document.write( "In seven years \n" ); document.write( "Age of Marilyn will be = m+7 \n" ); document.write( "Age of Rosie will be = r+7\r \n" ); document.write( "\n" ); document.write( "THEN\r \n" ); document.write( "\n" ); document.write( "In seven years the product of their ages will be 2 less than six times the product of their ages five years ago.\r \n" ); document.write( "\n" ); document.write( "(m+7)(r+7)=6[(m-5)(r-5)]-2 \n" ); document.write( "mr+7m+7r+49=6(mr-5m-5r+25)-2 \n" ); document.write( "mr+7m+7r+49=6mr-30m-30r+150-2 \n" ); document.write( "mr-6mr+7m+30m+30r+7r=150-2-49 \n" ); document.write( "-5mr+37m+37r=150-51 \n" ); document.write( "-5mr+37m+37r=99..................(2)\r \n" ); document.write( "\n" ); document.write( "Put the value of m from (1) to (2) \n" ); document.write( "-5(r-3)r+37(r-3)+37r=99 \n" ); document.write( "-5r^2+15r+37r-111+37r=99 \n" ); document.write( "-5r^2+89r-99-111=0 \n" ); document.write( "-5r^2+89r-200=0 \n" ); document.write( "Now solve for r \n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "r=15 or r = 2.8 (reject)\r \n" ); document.write( "\n" ); document.write( "Put r=15 in (1) \n" ); document.write( "m=r-3 \n" ); document.write( "m=15-3 \n" ); document.write( "m=12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Present age of Marilyn = m = 12 years old \n" ); document.write( "Present age of Rosie = r = 15 years old\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check \n" ); document.write( "====== \n" ); document.write( "Five years ago \n" ); document.write( "Age of Marilyn was = 7 \n" ); document.write( "Age of Rosie was = 10\r \n" ); document.write( "\n" ); document.write( "In seven years \n" ); document.write( "Age of Marilyn will be = 19 \n" ); document.write( "Age of Rosie will be = 22\r \n" ); document.write( "\n" ); document.write( "THEN\r \n" ); document.write( "\n" ); document.write( "In seven years the product of their ages will be 2 less than six times the product of their ages five years ago.\r \n" ); document.write( "\n" ); document.write( "19*22=6(7*10)-2 \n" ); document.write( "418=6(70)-2 \n" ); document.write( "418=420-2 \n" ); document.write( "418=418\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |