document.write( "Question 567635: Hi I am trying to help my daughter with her math homework and I know the answer to the question but I am really not sure how I came up with it. Here is the question.\r
\n" ); document.write( "\n" ); document.write( "Victor has 8 coins. He has 2 fewer dimes than nickels, and one more penny than nickels. How much money does he have?\r
\n" ); document.write( "\n" ); document.write( "In my head I figured out that there is going to be 1 dime, 3 nickels, and 4 pennies and that would of course equal 29 cents. Unfortunately we have to explain our answer and show the work and that is where I am stuck. \r
\n" ); document.write( "\n" ); document.write( "Thanks for your help!
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Algebra.Com's Answer #366653 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Let D = the number of dimes, N = the number of nickels, and P = the number of pennies.
\n" ); document.write( "From the problem description, you can write:
\n" ); document.write( "1) D+N+P = 8 \"Victor has 8 coins.\"
\n" ); document.write( "2) D = N-2 \"He has 2 fewer dimes than nickels.\"
\n" ); document.write( "3) P = N+1 \"...and one more penny than nickels.\"
\n" ); document.write( "Replace the D and the P in equation 1) with their equivalents from equations 2) and 3).
\n" ); document.write( "(N-2)+N+(N+1) = 8 Simplify this.
\n" ); document.write( "3N-1 = 8 Add 1 to both sides.
\n" ); document.write( "3N = 9 Now divide both sides by 3.
\n" ); document.write( "N = 3 and...
\n" ); document.write( "D = N-2
\n" ); document.write( "D = 3-2
\n" ); document.write( "D = 1 and...
\n" ); document.write( "P = N+1
\n" ); document.write( "P = 3+1
\n" ); document.write( "P = 4
\n" ); document.write( "So victor has 1 dime ($0.10), 3 nickels ($0.15), and 4 pennies ($0.04).
\n" ); document.write( "Add them together to get:
\n" ); document.write( "$0.29 or 29 cents.\r
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