document.write( "Question 567635: Hi I am trying to help my daughter with her math homework and I know the answer to the question but I am really not sure how I came up with it. Here is the question.\r
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document.write( "Victor has 8 coins. He has 2 fewer dimes than nickels, and one more penny than nickels. How much money does he have?\r
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document.write( "In my head I figured out that there is going to be 1 dime, 3 nickels, and 4 pennies and that would of course equal 29 cents. Unfortunately we have to explain our answer and show the work and that is where I am stuck. \r
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document.write( "Thanks for your help! \n" );
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Algebra.Com's Answer #366653 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Let D = the number of dimes, N = the number of nickels, and P = the number of pennies. \n" ); document.write( "From the problem description, you can write: \n" ); document.write( "1) D+N+P = 8 \"Victor has 8 coins.\" \n" ); document.write( "2) D = N-2 \"He has 2 fewer dimes than nickels.\" \n" ); document.write( "3) P = N+1 \"...and one more penny than nickels.\" \n" ); document.write( "Replace the D and the P in equation 1) with their equivalents from equations 2) and 3). \n" ); document.write( "(N-2)+N+(N+1) = 8 Simplify this. \n" ); document.write( "3N-1 = 8 Add 1 to both sides. \n" ); document.write( "3N = 9 Now divide both sides by 3. \n" ); document.write( "N = 3 and... \n" ); document.write( "D = N-2 \n" ); document.write( "D = 3-2 \n" ); document.write( "D = 1 and... \n" ); document.write( "P = N+1 \n" ); document.write( "P = 3+1 \n" ); document.write( "P = 4 \n" ); document.write( "So victor has 1 dime ($0.10), 3 nickels ($0.15), and 4 pennies ($0.04). \n" ); document.write( "Add them together to get: \n" ); document.write( "$0.29 or 29 cents.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |