document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=54398>Question 54398</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having trouble understanding system of equations. i have tried to work the problem out but im not sure what steps to take. can you help me on the problem 3x/2 + y/4=7<BR>\n" );
document.write( "x/5 - 2y/3 = 2 1/3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36664 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36664\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1st:3x/2 + y/4=7<BR>\n" );
document.write( "Multiply thru by 4 to get:<BR>\n" );
document.write( "2nd: 6x+y=28<BR>\n" );
document.write( "3rd: x/5 - 2y/3 = 2 1/3<BR>\n" );
document.write( "Multiply thru by 15 to get:<BR>\n" );
document.write( "4th: 3x-19y=35<BR>\n" );
document.write( "To eliminate the \"x\" terms multiply thru 4th by 2 to get:<BR>\n" );
document.write( "5th: 6x-38y=70<BR>\n" );
document.write( "Subtract 5th from 2nd to get:<BR>\n" );
document.write( "6th: 39y=-42<BR>\n" );
document.write( "Then y=-14/13<BR>\n" );
document.write( "Substitute that into 2nd to solve for \"x\":<BR>\n" );
document.write( "6x-14/13 = 28<BR>\n" );
document.write( "6x=14/13 + 364/13<BR>\n" );
document.write( "6x = 378/13<BR>\n" );
document.write( "x= 63/13<BR>\n" );
document.write( "Solution:<BR>\n" );
document.write( "x=63/13 y=-14/13<BR>\n" );
document.write( "cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );