document.write( "Question 567535: If the perimeter of a regtangle is 80m and the area is 300 m2 what is the length and width of the rectangle. What is the formula for working out this? \n" ); document.write( "
Algebra.Com's Answer #366626 by mananth(16946)\"\" \"About 
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perimeter of recatngle = 2(L+W)\r
\n" ); document.write( "\n" ); document.write( "2(L+W)=80\r
\n" ); document.write( "\n" ); document.write( "Area of rectangle = L*W\r
\n" ); document.write( "\n" ); document.write( "L*W= 300
\n" ); document.write( "L= 300/w\r
\n" ); document.write( "\n" ); document.write( "substitute L in the first equation\r
\n" ); document.write( "\n" ); document.write( "\"2%28%28300%2FW%29%2BW%29=80\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%28%28300%2BW%5E2%29%2FW%29=80\"\r
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\n" ); document.write( "\n" ); document.write( "Multiply by W\r
\n" ); document.write( "\n" ); document.write( "\"2%28300%2BW%5E2%29=+80W\"\r
\n" ); document.write( "\n" ); document.write( "divide by 2\r
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\n" ); document.write( "\n" ); document.write( "\"300%2BW%5E2=40W%0D%0A%0D%0A%0D%0A%7B%7B%7BW%5E2-40W%2B300%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"W%5E2-30W-10W%2B300=0\"\r
\n" ); document.write( "\n" ); document.write( "W(W-30)-10(W-30)=0\r
\n" ); document.write( "\n" ); document.write( "(W-30)(W-10)=0\r
\n" ); document.write( "\n" ); document.write( "W= 30 OR 10\r
\n" ); document.write( "\n" ); document.write( "The dimensions are 30m by 10m\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca\r
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