document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=567286>Question 567286</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the measure of two supplementary angles are in the ratio 5:7. what is the measure of the larger angle?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #366589 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=366589\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the measure of two supplementary angles are in the ratio 5:7. <BR>\n" );
document.write( "what is the measure of the larger angle?<BR>\n" );
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document.write( "Let x = the multiplier<BR>\n" );
document.write( "then<BR>\n" );
document.write( "one angle = 5x<BR>\n" );
document.write( "other angle = 7x<BR>\n" );
document.write( "Supplementary, therefore<BR>\n" );
document.write( "5x + 7x = 180<BR>\n" );
document.write( "12x = 180<BR>\n" );
document.write( "x = 180/12<BR>\n" );
document.write( "x = 15 is the multiplier<BR>\n" );
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document.write( "therefore, the angle are:<BR>\n" );
document.write( "15*5 = 75 degrees<BR>\n" );
document.write( "15*7 = 105 degrees is the larger angle<BR>\n" );
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