document.write( "Question 567516: a kayaker can paddle 12 mi in 2 h moving with the river current. paddling at the same pace, the trip back against the current takes 4 h. assume that the river current is constant. find what the kayaker's speed would be in still water. \n" ); document.write( "
Algebra.Com's Answer #366584 by stanbon(75887)\"\" \"About 
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a kayaker can paddle 12 mi in 2 h moving with the river current. paddling at the same pace, the trip back against the current takes 4 h. assume that the river current is constant. find what the kayaker's speed would be in still water.
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\n" ); document.write( "Downstream DATA:
\n" ); document.write( "distance = 12 miles ; time = 2 hours ; rate = 12/2 = 6 mph
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\n" ); document.write( "Upstream DATA:
\n" ); document.write( "distance = 12 miles ; time = 4 hrs ; rate = 12/4 = 3 mph
\n" ); document.write( "----
\n" ); document.write( "Equations:
\n" ); document.write( "Downstream: b + c = 6
\n" ); document.write( "Upstream::: b - c = 3
\n" ); document.write( "------
\n" ); document.write( "Add to get:
\n" ); document.write( "2b = 9
\n" ); document.write( "b = 4.5 mph (speed of the boat in still water.
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\n" ); document.write( "Solve for \"c\":
\n" ); document.write( "b + c = 6
\n" ); document.write( "4.5 + c = 6
\n" ); document.write( "c = 1.5 mph (speed of the current)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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