document.write( "Question 567450: Two investments earn an annual income of $478.40. One investment earns an annual simple interest rate of 6.5%, and the other investment earns an annual simple interest rate of 5.4%. The total amount invested is $7,800. How much is invested in each account? \n" ); document.write( "
Algebra.Com's Answer #366571 by mananth(16946)\"\" \"About 
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Investment Part I 6.50% per annum ----x
\n" ); document.write( "Investment part II 5.40% per annum ----y
\n" ); document.write( "The sum of the investments is $7,800.00
\n" ); document.write( "The sum of individual interests = $478.40
\n" ); document.write( "x+y=7800 ------------------------1
\n" ); document.write( "6.50%x+ 5.40%y= $478.40
\n" ); document.write( "Multiply by 100
\n" ); document.write( "6.5x+5.4y= $47,840.00 --------2
\n" ); document.write( "
\n" ); document.write( "Multiply (1) by -6.5
\n" ); document.write( "we get
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\n" ); document.write( "-6.5x-6.5y= -50700.00
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\n" ); document.write( "Add this to (2)
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\n" ); document.write( "0x-1.1y =-$2,860.00
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\n" ); document.write( "divide by-1.1
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\n" ); document.write( "y = $2,600.00 investment at 5.40%
\n" ); document.write( "Balance $5,200.00 investment at 6.50%
\n" ); document.write( "CHECK
\n" ); document.write( "$5,200.00 @ 6.50% $338.00
\n" ); document.write( "$2,600.00 @ 5.40% $140.40
\n" ); document.write( "Total -------------------- $478.40
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