document.write( "Question 567450: Two investments earn an annual income of $478.40. One investment earns an annual simple interest rate of 6.5%, and the other investment earns an annual simple interest rate of 5.4%. The total amount invested is $7,800. How much is invested in each account? \n" ); document.write( "
Algebra.Com's Answer #366571 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Investment Part I 6.50% per annum ----x \n" ); document.write( "Investment part II 5.40% per annum ----y \n" ); document.write( "The sum of the investments is $7,800.00 \n" ); document.write( "The sum of individual interests = $478.40 \n" ); document.write( "x+y=7800 ------------------------1 \n" ); document.write( "6.50%x+ 5.40%y= $478.40 \n" ); document.write( "Multiply by 100 \n" ); document.write( "6.5x+5.4y= $47,840.00 --------2 \n" ); document.write( " \n" ); document.write( "Multiply (1) by -6.5 \n" ); document.write( "we get \n" ); document.write( " \n" ); document.write( "-6.5x-6.5y= -50700.00 \n" ); document.write( " \n" ); document.write( "Add this to (2) \n" ); document.write( " \n" ); document.write( "0x-1.1y =-$2,860.00 \n" ); document.write( " \n" ); document.write( "divide by-1.1 \n" ); document.write( " \n" ); document.write( "y = $2,600.00 investment at 5.40% \n" ); document.write( "Balance $5,200.00 investment at 6.50% \n" ); document.write( "CHECK \n" ); document.write( "$5,200.00 @ 6.50% $338.00 \n" ); document.write( "$2,600.00 @ 5.40% $140.40 \n" ); document.write( "Total -------------------- $478.40 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |