document.write( "Question 54409This question is from textbook ALGEBRA AND TRIGONOMETRY
\n" ); document.write( ": SOMEONE PLEASE HELP ME WITH THIS PROBLEM:
\n" ); document.write( "IF f(x)=x(x+3)(x-1), use interval notation to give all values of x where f(x)>0.\r
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Algebra.Com's Answer #36657 by Nate(3500)\"\" \"About 
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f(x) must be greater than the value of zero
\n" ); document.write( "0 < x(x + 3)(x - 1)
\n" ); document.write( "The zeros for x(x + 3)(x - 1) is at x=0, x=-3, and x=1.
\n" ); document.write( "Pick Points:
\n" ); document.write( "<```(-3)```(0)```(1)```>
\n" ); document.write( "x = -4
\n" ); document.write( "0 < (-4)(-4 + 3)(-4 - 1)
\n" ); document.write( "0 < (-4)(-1)(-5)
\n" ); document.write( "0 < -20 Not True
\n" ); document.write( "<---(-3)```(0)```(1)```>
\n" ); document.write( "x = -1
\n" ); document.write( "0 < (-1)(-1 + 3)(-1 - 1)
\n" ); document.write( "0 < (-1)(2)(-2)
\n" ); document.write( "0 < 4 True
\n" ); document.write( "<---(-3)====(0)```(1)```>
\n" ); document.write( "x = 0.5
\n" ); document.write( "0 < (0.5)(0.5 + 3)(0.5 - 1) We already know we will get a negative number, so this is false.
\n" ); document.write( "<---(-3)====(0)----(1)```>
\n" ); document.write( "x = 2
\n" ); document.write( "0 < (2)(2 + 3)(2 - 1)
\n" ); document.write( "0 < (2)(5)(1)
\n" ); document.write( "0 < 10 This is true.
\n" ); document.write( "<---(-3)====(0)----(1)====>
\n" ); document.write( "(-3,0)U(1,+\"infinity\") \n" ); document.write( "
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