document.write( "Question 567371: There were 510 people at a play. The admission price was 2 for adults and 1 for children. The admission receipts were 810. How many adults and how many children attended? \n" ); document.write( "
Algebra.Com's Answer #366518 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Adults = x
\n" ); document.write( "Children = 510-x
\n" ); document.write( "Total receipts = 810\r
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\n" ); document.write( "\n" ); document.write( "Admission price for Adults = 2
\n" ); document.write( "Admission price for Children = 1\r
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\n" ); document.write( "\n" ); document.write( "(Admission price for Adults)(Adults)+ (Admission price for Children)(Children) = Total receipts\r
\n" ); document.write( "\n" ); document.write( "(2)(x)+(1)(510-x)=810
\n" ); document.write( "2x+510-x=810
\n" ); document.write( "x=810-510
\n" ); document.write( "x=300\r
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\n" ); document.write( "\n" ); document.write( "Adults = x = 300
\n" ); document.write( "Children = 510-x = 510-300 = 210\r
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\n" ); document.write( "\n" ); document.write( "Check
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\n" ); document.write( "300*2+210*1=810
\n" ); document.write( "600+210=810
\n" ); document.write( "810=810\r
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