document.write( "Question 567271: A car starts with the speed 60 km/hr from prayad at 3 p.m. After 1 hour a second car starts with the speed 80 km/hr on the same track to cross to the first car. After how many kms the second car wil meet the first? \n" ); document.write( "
Algebra.Com's Answer #366489 by mananth(16946)\"\" \"About 
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\n" ); document.write( "Car A speed = 60 km/h\r
\n" ); document.write( "\n" ); document.write( "Car B speed = 80 km/h\r
\n" ); document.write( "\n" ); document.write( "when car B starts Car A has traveled 60 km\r
\n" ); document.write( "\n" ); document.write( "Let the distance they meet be x km\r
\n" ); document.write( "\n" ); document.write( "they are going in the same direction\r
\n" ); document.write( "\n" ); document.write( "subtract their speeds 80-60=20 km/h
\n" ); document.write( "Time taken by car A = time taken by Car B\r
\n" ); document.write( "\n" ); document.write( "(x-60)/60 = x/80\r
\n" ); document.write( "\n" ); document.write( "80(x-60)=60x
\n" ); document.write( "80x-480=60x
\n" ); document.write( "80x-60x= 480
\n" ); document.write( "20x=480
\n" ); document.write( "/20
\n" ); document.write( "x= 24 km
\n" ); document.write( "
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