document.write( "Question 54404: I am stuck on correct answer for:\r
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document.write( "square root of 48 - sq. root of 12 =\r
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document.write( "I am not using a specific book. I am just practicing...\r
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Algebra.Com's Answer #36648 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! SQRT48=SQRT16*3 & THE SQRT16*3=4SQRT3 REMOVING THE SQRT OF 16=4 OUTSIDE THE SQRT. \r \n" ); document.write( "\n" ); document.write( "THEN THE SQRT12=SQRT4*3 OR 2SQRT3 REMOVING THE SQRT OF 4=2 OUTSIDE THE SQRT.\r \n" ); document.write( "\n" ); document.write( "SUBTRACTING 2SQRT3 FROM 4SQRT3 WE GET 2SQRT3 \n" ); document.write( " |