document.write( "Question 54404: I am stuck on correct answer for:\r
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Algebra.Com's Answer #36648 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
SQRT48=SQRT16*3 & THE SQRT16*3=4SQRT3 REMOVING THE SQRT OF 16=4 OUTSIDE THE SQRT. \r
\n" ); document.write( "\n" ); document.write( "THEN THE SQRT12=SQRT4*3 OR 2SQRT3 REMOVING THE SQRT OF 4=2 OUTSIDE THE SQRT.\r
\n" ); document.write( "\n" ); document.write( "SUBTRACTING 2SQRT3 FROM 4SQRT3 WE GET 2SQRT3
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