document.write( "Question 567210: A boat takes 2 hours to go 50 KM from A to B down the stream. But the return journey from B to A. It take 3 hours. Find the uniform speed of the boat in still water and the uniform speed the stream. (Ans. 125/6 KM/H and 25/6 KM/H) \n" ); document.write( "
Algebra.Com's Answer #366478 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Boat speed =x km/h
\n" ); document.write( "current speed =y km/h
\n" ); document.write( "against current x-y 3.00 hours
\n" ); document.write( "with current x+y 2.00 hours
\n" ); document.write( "
\n" ); document.write( "Distance = same= 50 km
\n" ); document.write( "t=d/r
\n" ); document.write( "50/(x-y )=3.00
\n" ); document.write( "3(x-y)= 50.00
\n" ); document.write( "3x-3y= 50 ....................1
\n" ); document.write( "50/(x+y )=2.00
\n" ); document.write( "2.00(x+y)=50
\n" ); document.write( "2.00x+2.00y=50 ...............2
\n" ); document.write( "Multiply (1) by 2.00
\n" ); document.write( "Multiply (2) by 3.00
\n" ); document.write( "we get
\n" ); document.write( "6x-6y = 100
\n" ); document.write( "6x+6y = 150
\n" ); document.write( "12x=250
\n" ); document.write( "/12
\n" ); document.write( "x = 125/6 km/h
\n" ); document.write( "
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "3 x -3 y = 50
\n" ); document.write( "125/2 -3 y = 50
\n" ); document.write( "-3 y = 50 -125/2
\n" ); document.write( "-3 y = -25/2
\n" ); document.write( " y = 25/6 km/h
\n" ); document.write( "The speed of Boat = 125/6 km/h
\n" ); document.write( "The speed of current = 25/6 km/h
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( " \n" ); document.write( "
\n" );