document.write( "Question 567191: Things did not go quite as planned. You invested $10,250.00, part of it in stock that paid 12.5% annual interest. However, the rest of the money suffered a 6.7% loss. If the total annual income from both investments was $346.00, how much was invested at each rate? \n" ); document.write( "

Algebra.Com's Answer #366446 by stanbon(75887) $\"\"$ $\"About$

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You invested $10,250.00, part of it in stock that paid 12.5% annual interest. However, the rest of the money suffered a 6.7% loss. If the total annual income from both investments was $346.00, how much was invested at each rate?
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\n" ); document.write( "Quantity Eq::: x + y = 10,250
\n" ); document.write( "Interest Eq::0.125x - 0.067y = 346
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\n" ); document.write( "Multiply thru the Interest equation by 1000
\n" ); document.write( "Multiply thru the Quantity Eq. by 125
\n" ); document.write( "--------------------------
\n" ); document.write( "125x + 125y = 125*10,250
\n" ); document.write( "125x - 67y = 346000
\n" ); document.write( "---------------------------------------
\n" ); document.write( "Subtract and solve for \"y\":
\n" ); document.write( "192y = $935,250
\n" ); document.write( "y = $4871.09 (amt. invested at 6.7%
\n" ); document.write( "Solve for \"x\":
\n" ); document.write( "x + y = 10,250
\n" ); document.write( "x + 4671.09 = 10,250
\n" ); document.write( "x = $5378.91 (amt. invested at 12.5%
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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