document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=54389>Question 54389</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3 times the width. The perimeter is 96 cm. Find the width and length. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36643 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36643\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> PERIMETER IS EQUAL TO 2 TIMES THE LENGTH PLUS 2 TIMES THE WIDTH <BR>\n" );
document.write( "THUS P=2L+2W OR 96=2*3W+2*W OR 96=6W+2W OR 96=8W OR W=96/8 OR W=12 THUS\r<BR>\n" );
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document.write( "86=2*L+2*12 OR 96=2*L+24 OR 96-24=2L OR 72=2L OR 72/2=L OR L=36\r<BR>\n" );
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document.write( "PROOF 86=2*36+2*12 OR 86=72+24 OR 86=86 WHEN THE LENGTH (36) IS 3 TIMES THE WIDTH (12) 3*12=36. </SPAN>\n" );
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