document.write( "Question 566568: my question:
\n" ); document.write( "A chemist mixes 12l of a solution tht is 45% acid wiht 8l of a sotution that is 70 % acid, what is the % of acid of the mixture?
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Algebra.Com's Answer #366269 by Maths68(1474)\"\" \"About 
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Solution A
\n" ); document.write( "Amount =121
\n" ); document.write( "Concentration =45% = 0.45\r
\n" ); document.write( "\n" ); document.write( "Solution B
\n" ); document.write( "Amount = 81
\n" ); document.write( "Concentration =70% = 0.70\r
\n" ); document.write( "\n" ); document.write( "Mixture
\n" ); document.write( "Amount =(81+121)=202
\n" ); document.write( "Concentration =x\r
\n" ); document.write( "\n" ); document.write( "[Amount Solution A * Concentration A] + [Amount Solution B * Concentration of B] = Amount of Mixture * Concentration of Mixture\r
\n" ); document.write( "\n" ); document.write( "(121)(0.45)+(81)(0.70)=(202)(x)
\n" ); document.write( "54.45+56.70=202x
\n" ); document.write( "111.15=202x
\n" ); document.write( "111.15/202=202x/202
\n" ); document.write( "0.550248=x
\n" ); document.write( "x=0.550248\r
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\n" ); document.write( "\n" ); document.write( "Mixture
\n" ); document.write( "Amount =(81+121)=202
\n" ); document.write( "Concentration =x = 0.550248 = 0.550248/100 = 55.0248%\r
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\n" ); document.write( "\n" ); document.write( "Chemist will have 202 of 55.0248% acid mixture.\r
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