document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=566459>Question 566459</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is -3(3x+15)-(10+x)=35 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #366212 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=366212\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  -3(3x+15)-(10+x)=35\r<BR>\n" );
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document.write( "-9x-45-10-x=35\r<BR>\n" );
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document.write( "add up like terms\r<BR>\n" );
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document.write( "-10x-55=35\r<BR>\n" );
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document.write( "-10x=55+35\r<BR>\n" );
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document.write( "-10x=90\r<BR>\n" );
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document.write( "/-10<BR>\n" );
document.write( "x=-9 </SPAN>\n" );
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