document.write( "Question 566298: Bottle A, containing 12L of 15% acid, is combined with bottle B, containing 3L of 25% acid. Bottle C is 26% acid. How much of each solution is neede to have 24L of a 20% acid solution? \n" ); document.write( "
Algebra.Com's Answer #366199 by ankor@dixie-net.com(22740)\"\" \"About 
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Bottle A, containing 12L of 15% acid, is combined with bottle B, containing 3L of 25% acid.
\n" ); document.write( " Bottle C is 26% acid.
\n" ); document.write( "How much of each solution is needed to have 24L of a 20% acid solution?
\n" ); document.write( ":
\n" ); document.write( "Let C = amt of 26% acid solution required
\n" ); document.write( ":
\n" ); document.write( ".26C + .15(12) + .25(3) = .20(24)
\n" ); document.write( "Do the math
\n" ); document.write( ".26C + 1.8 + .75 = 4.8
\n" ); document.write( ".26C + 2.55 = 4.8
\n" ); document.write( ".26C = 4.8 - 2.55
\n" ); document.write( ".26C = 2.25
\n" ); document.write( "C = 2.25/.26
\n" ); document.write( "C = 8.654 L of 26% acid
\n" ); document.write( ":
\n" ); document.write( "\"How much of each solution is needed to have 24L of a 20% acid solution?\"
\n" ); document.write( "12L of A
\n" ); document.write( "3 L of B
\n" ); document.write( "8.654L of C \n" ); document.write( "
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