document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=566340>Question 566340</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i can not figure out 7 4/5 times 2 1/3. could you please help me<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #366195 by </B><A HREF=/tutors/aboutme.mpl?userid=Tias_411><B>Tias_411(14)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Tias_411><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Tias_411><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=366195\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> its best to convert them to improper fractions first.. 7 4/5= 39/5 and 2 1/3= 7/3. then you just multiply the numerators and denominators. 39*7 and 5*3.. that gives you 273/15. then you turn that back into a mixed number.. giving you an answer of 18 3/15 which is also equal to 18 1/5 in lowest terms.. i think..  </SPAN>\n" );
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