document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=566323>Question 566323</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How to solve a linear equation with substitution. 4x-2y=4  y=2x-2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #366184 by </B><A HREF=/tutors/aboutme.mpl?userid=Tias_411><B>Tias_411(14)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Tias_411><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Tias_411><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=366184\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> substitute what you have for y into your original problem of 4x-2y= 4. if y is 2x-2 then your new problem is now <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+4x-2%282x-2%29=+4+ ALIGN=MIDDLE  ALT=\"+4x-2%282x-2%29=+4+\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
document.write( "\n" );
document.write( "4x-2(2x-2)= 4<BR>\n" );
document.write( "4x-4x+4= 4 *distributive property<BR>\n" );
document.write( "0+4= 4<BR>\n" );
document.write( "4= 4 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );