document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=566317>Question 566317</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many pounds each of a $3.50 blend of nuts and a $5.00 blend of nuts is mixed to get 10 pounds of a $4.00 blend of nuts? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #366183 by </B><A HREF=/tutors/aboutme.mpl?userid=ad_alta><B>ad_alta(240)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ad_alta><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ad_alta><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=366183\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let 'c' be the number of pounds of cheaper nuts and 'e' the number of pounds of expensive nuts. Then we have the equations c+e=10 and (3.5*c+5*e)/(c+e)=4. Substitute c+e=10 and c=10-e into the second equation to get (3.5*(10-e)+5*e)/(10)=4. Solving, we get e=3.33 and c=6.67. </SPAN>\n" );
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