document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=566203>Question 566203</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 44 inches.Find the dimension if the width is two inches longer than three times the length.Then find the area of the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #366151 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=366151\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 44 inches.Find the dimension if the width is two inches longer than three times the length.Then find the area of the rectangle.<BR>\n" );
document.write( "**<BR>\n" );
document.write( "let x=length of rectangle<BR>\n" );
document.write( "3x+2=width of rectangle<BR>\n" );
document.write( "Perimeter=2*(length+width)=44<BR>\n" );
document.write( "=2(x+3x+2)=2(4x+2)=8x+4=44<BR>\n" );
document.write( "8x=40<BR>\n" );
document.write( "x=5 (length<BR>\n" );
document.write( "3x+2=17 (width)<BR>\n" );
document.write( "Area of rectangle=length*width=5*17=85 sq in </SPAN>\n" );
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