document.write( "Question 54342This question is from textbook Elementary and Intermediate Algebra
\n" ); document.write( ": A boxing ring is in the shape of a square with 20 ft. on each side. How far apart are the fighters when they are in opposite corners of the ring? \n" ); document.write( "

Algebra.Com's Answer #36612 by checkley71(8403) $\"\"$ $\"About$

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THIS PROBLEM IS A RIGHT TRIANGLE WITH 2 SIDES = TO 20 FEET AND THE HYPOTENUSE THE DISTANCE BETWEEN THE OPPOSITE CORNERS. THUS THE FORMULA A^2+B^2=C^2 THUS \r
\n" ); document.write( "\n" ); document.write( "20^2+20^2=C^2 OR 400+400=C^2 OR 800=C^2 OR C=28.28 FEET FOR THE DIAGONAL OF THE 20 FOOT SQUARE RING.\r
\n" ); document.write( "\n" ); document.write( "c^2 is the same as c*c or (c squared). 800 IS THE SAME AS 28.28*28.28 or 28.28 is the square root of 800 or 800=28.28*28.28 (or 28.28^2 or 28.28 squared=800)\r
\n" ); document.write( "\n" ); document.write( "another example: x^2=25 or x^2=x*x & 25=5*5 thus the sqare root of x^2=x & the square root of 25=5 then x=5. \n" ); document.write( "

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