document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=566079>Question 566079</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me i am ot soo good with word problems. if u can please help me i would appreciate it!!\r<BR>\n" );
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document.write( "tim needs to find the height of a tower surrounded by a fence, which prevents direct measurement of the tower's shadow length. Tim was instead able to find that the shadow was 650 feet longer at a 30 degree angle as compared to a 45 degree angle of the sun. Help Tim solve for the tower height.<BR>\n" );
document.write( "please help me!!!! <BR>\n" );
document.write( "Thank you!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #366093 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=366093\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the shadow at 45 deg be x<BR>\n" );
document.write( "at 30 deg it is x+650 ft\r<BR>\n" );
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document.write( "let height of tower be h ft\r<BR>\n" );
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document.write( "Tan 45 = h/x\r<BR>\n" );
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document.write( "but tan 45 = 1<BR>\n" );
document.write( "so h = x\r<BR>\n" );
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document.write( "Tan 30 = h/(h+650)\r<BR>\n" );
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document.write( "1/sqrt(3)= h/(h+650)\r<BR>\n" );
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document.write( "h+650 = h sqrt(3)<BR>\n" );
document.write( "hsqrt(3)-h = 650\r<BR>\n" );
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document.write( "h(sqrt(3)-1)=650\r<BR>\n" );
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document.write( "h= 650/(sqrt(3)-1)\r<BR>\n" );
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document.write( "h= 888 ft  </SPAN>\n" );
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