document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=566035>Question 566035</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ok i have ABSOLUTLEY NO CLUE WHAT TO DO I AM SOOO LOST ! PLEASE SOMEONE HELPME!!<BR>\n" );
document.write( "Find the radius of the right cylinder shown, in which the height of the cylinder is equal to the diameter.\r<BR>\n" );
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document.write( "ok, soo what i did is find the surface area.<BR>\n" );
document.write( "S=2*pi*radius^2+28pi*raduis<BR>\n" );
document.write( "so i plugged in the numbers<BR>\n" );
document.write( "150pi=2pir^2+2pir(2r)\r<BR>\n" );
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document.write( "after that i dont know what todo.. HONESTLEY i dont even think i did it right... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #366082 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=366082\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 150pi=2pir^2+2pir(r)\r<BR>\n" );
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document.write( "I presume 150 pi is the surface area\r<BR>\n" );
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document.write( "150pi=2pir^2+2pir^2\r<BR>\n" );
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document.write( "150pi=4pir^2\r<BR>\n" );
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document.write( "divide by 4pi\r<BR>\n" );
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document.write( "37.5=r^2\r<BR>\n" );
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document.write( "r= sqrt(37.5)\r<BR>\n" );
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document.write( "r=6.12<BR>\n" );
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