document.write( "Question 566037: The product of two consecutive odd integers is 58 less than the square of the next consecutive odd integer. Find the three integers. \r
\n" ); document.write( "\n" ); document.write( "let 2x+1 = 1st odd integer
\n" ); document.write( "2x+3 = 2nd odd integer
\n" ); document.write( "2x+5 = 3rd odd integer\r
\n" ); document.write( "\n" ); document.write( "Please help me in completing the solution! THANKS :)
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Algebra.Com's Answer #366071 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
you can also work it out this way\r
\n" ); document.write( "\n" ); document.write( "let the consequtive odd numbers be x,x+2,x+4\r
\n" ); document.write( "\n" ); document.write( "x(x+2)=(x+4)^2-58\r
\n" ); document.write( "\n" ); document.write( "x^2+2x=x^2+8x+16-58\r
\n" ); document.write( "\n" ); document.write( "x^2 cancels off
\n" ); document.write( "2x-8x=16-58\r
\n" ); document.write( "\n" ); document.write( "-6x=-42\r
\n" ); document.write( "\n" ); document.write( "/6
\n" ); document.write( "x=7\r
\n" ); document.write( "\n" ); document.write( "the numbers are 7,9,11\r
\n" ); document.write( "\n" ); document.write( "CHECK\r
\n" ); document.write( "\n" ); document.write( "7*9=63\r
\n" ); document.write( "\n" ); document.write( "11^2=121\r
\n" ); document.write( "\n" ); document.write( "121-58=63\r
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