document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=54349>Question 54349</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has two salt solutions. One solution is 20% salt and the other if 50% salt. How many liters of each must be used to produce 600 liters of a solution that is 10% salt? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36607 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36607\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> YOU CAN'T MIX A 20% SOLUTION WITH A 50% SOLUTION AND GET A 10% SOLUTION WITHOUT ADDING WATER OR SOME OTHER NON-SALT SOLUTION. THE HIGH & LOW SOLUTIONS ARE 599*.2+1*.5=600X OR 119.8+.5=600X OR 120.3=600X OR 120.3/600=X OR X=20.09% SOLUTION AND A MAX SOLUTION OF 599*.5+1*.2=600X OR 299.5+.2=600X OR 299.7/600=X OR X=49.95%. \r<BR>\n" );
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