document.write( "Question 565377: A mother is twice as old as her daughter. 8 yrs from now she will be twenty yrs. than her daughter. how old is mother now? \n" ); document.write( "

Algebra.Com's Answer #366025 by Maths68(1474) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let
\n" ); document.write( "Present age of Mother = m
\n" ); document.write( "Present age of Daughter = d\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Mother is twice as old as her daughter
\n" ); document.write( "m=2d............(1)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "8 yrs from now
\n" ); document.write( "Mother will be = m+8
\n" ); document.write( "Daughter will be = d+8\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Then\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "she will be twenty yrs. than her daughter
\n" ); document.write( "m+8=(d+8)+20
\n" ); document.write( "m+8=d+8+20
\n" ); document.write( "m+8=d+28
\n" ); document.write( "m=d+28-8
\n" ); document.write( "m=d+20................(2)
\n" ); document.write( "Put the value of m from (1) to (2)
\n" ); document.write( "2d=d+20
\n" ); document.write( "2d-d=20
\n" ); document.write( "d=20
\n" ); document.write( "Put the value of d in (1)
\n" ); document.write( "m=2d
\n" ); document.write( "m=2(20)
\n" ); document.write( "m=40\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Present age of Mother = m = 40 years old
\n" ); document.write( "Present age of Daughter = d = 20 years old\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );