document.write( "Question 54340This question is from textbook Elementary and Intermediate Algebra
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document.write( ": The total profit (in dollars) for sales of x rowing machines is given by
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document.write( "P(x)=-0.2x^2+300x-200. What is the profit if 500 are sold? For what value of x will the profit be at a maximum? \n" );
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Algebra.Com's Answer #36601 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! For the first part substitute 500 in for x in the profit function: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "=-.2(250,000)+300(500)-200 \n" ); document.write( "=-50,000+150,000-200 \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "For the second part, graphically, this is an upside down parabola. It's highest point is its vertex. The formula for finding the x value of a vertex of a parabola written in standard \n" ); document.write( "In your case a=-.2 and b=300, plug them into your formula and you have: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "You weren't asked, but your maximum profit can be found by plugging in x=750 into your original equation P(750)=$112,300. \n" ); document.write( "Happy Calculating!!! \n" ); document.write( " \n" ); document.write( " |