document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=565813>Question 565813</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a certain rectangle is 288yd2.  The  perimeter is 68yd. If you double the length and width, what will be the area and perimeter of the new rectangle?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #366002 by </B><A HREF=/tutors/aboutme.mpl?userid=ad_alta><B>ad_alta(240)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ad_alta><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ad_alta><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=366002\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Doubling the length and width will also double the perimeter (which would be 136). The area would be (2w)(2l)=4wl=4A (for area 'A,' width 'w,' and length 'l'); thus, it would be multiplied by 4 (which would be 1152). </SPAN>\n" );
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