document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=565828>Question 565828</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How does the length of a rectangle change when the width is decreased by 6 units and its perimeter remains the same ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #365998 by </B><A HREF=/tutors/aboutme.mpl?userid=ad_alta><B>ad_alta(240)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ad_alta><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ad_alta><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=365998\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the perimeter be 'P' and the length and width 'l' and 'w' respectively. We know 2w+2l=P. We also know that l' (the new length) satisfies 2l'+2(w-6)=P=2l+2w. This means that l'=l+6. This is sort of obvious, but the new length must be 6 units longer [but now you've actually proved that result!]. </SPAN>\n" );
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