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You can put this solution on YOUR website!
I think you mean \"4x^2-3=9.\" Then 4x^2-12=0 implies 4(x^2-3)=0. Thus, x={+/-}sqrt(3). \n" ); document.write( "
| Algebra.Com's Answer #365980 by ad_alta(240) You can put this solution on YOUR website! I think you mean \"4x^2-3=9.\" Then 4x^2-12=0 implies 4(x^2-3)=0. Thus, x={+/-}sqrt(3). \n" ); document.write( " |