document.write( "Question 565838: Tom has two loans totaling 18000.00 one loan has a interest of 4.25% the other loan is at 6% after six years tom has a total interest of 5400.00 what is the total of both loans \n" ); document.write( "
Algebra.Com's Answer #365953 by mananth(16946)\"\" \"About 
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Loan A 4.25% per annum ----x
\n" ); document.write( "Loan B 6.00% per annum ----y \r
\n" ); document.write( "\n" ); document.write( "for 6 years interest interest = 5400
\n" ); document.write( "for 1 year it will be 900
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\n" ); document.write( "x+y= 18000 ------------------------1
\n" ); document.write( "4.25%x+6.00%y=$900.00
\n" ); document.write( "Multiply by 100
\n" ); document.write( "4.25x+6y=$90,000.00 --------2
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\n" ); document.write( "Multiply (1) by -4.25
\n" ); document.write( "we get
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\n" ); document.write( "-4.25 x -4.25 y = -76500.00
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\n" ); document.write( "Add this to (2)
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\n" ); document.write( "0 x 1.75 y = $13,500.00
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\n" ); document.write( "divide by 1.75
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\n" ); document.write( "y = $7,714.29 investment at 6.00%
\n" ); document.write( "Balance $10,285.71 investment at 4.25%
\n" ); document.write( "CHECK
\n" ); document.write( "$10,285.71 $437.14
\n" ); document.write( "$7,714.29 $462.86
\n" ); document.write( "Total $900.00
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