document.write( "Question 54273: If I invest $18,750 in two different accounts and one account earns 12% interest and the other earns 10% interest, and at the end of the year have a total $20,867 (original amount + interest), how much did I invest in each account? \n" ); document.write( "
Algebra.Com's Answer #36594 by stanbon(75887)\"\" \"About 
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If I invest $18,750 in two different accounts and one account earns 12% interest and the other earns 10% interest, and at the end of the year have a total $20,867 (original amount + interest), how much did I invest in each account?
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\n" ); document.write( "Let amount invested at 12% be \"x\".
\n" ); document.write( "Interest on this money is 0.12x.
\n" ); document.write( "Amount invested at 10% is \"18750-x\"
\n" ); document.write( "Interest on this money is 0.10(18750-x)=1875-0.1x
\n" ); document.write( "EQUATION:
\n" ); document.write( "interest + interest = 20,867-18750
\n" ); document.write( "0.12x +1875-0.1x = 2117
\n" ); document.write( "o.02x= 242
\n" ); document.write( "x=$12,110 (Amount invested at 12%)
\n" ); document.write( "18750-x= $6640 (Amount invested at 10%)
\n" ); document.write( "Chers,
\n" ); document.write( "Stan H.
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