document.write( "Question 54273: If I invest $18,750 in two different accounts and one account earns 12% interest and the other earns 10% interest, and at the end of the year have a total $20,867 (original amount + interest), how much did I invest in each account? \n" ); document.write( "
Algebra.Com's Answer #36594 by stanbon(75887) ![]() You can put this solution on YOUR website! If I invest $18,750 in two different accounts and one account earns 12% interest and the other earns 10% interest, and at the end of the year have a total $20,867 (original amount + interest), how much did I invest in each account? \n" ); document.write( "---------------- \n" ); document.write( "Let amount invested at 12% be \"x\". \n" ); document.write( "Interest on this money is 0.12x. \n" ); document.write( "Amount invested at 10% is \"18750-x\" \n" ); document.write( "Interest on this money is 0.10(18750-x)=1875-0.1x \n" ); document.write( "EQUATION: \n" ); document.write( "interest + interest = 20,867-18750 \n" ); document.write( "0.12x +1875-0.1x = 2117 \n" ); document.write( "o.02x= 242 \n" ); document.write( "x=$12,110 (Amount invested at 12%) \n" ); document.write( "18750-x= $6640 (Amount invested at 10%) \n" ); document.write( "Chers, \n" ); document.write( "Stan H. \n" ); document.write( " |