document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=565258>Question 565258</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Eight people are going to line up to get on a bus. Three of those people are husband, wife and (2.5 pts) their daughter that must follow each other when they line up to get on the bus. How many ways are possible for the line up? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #365936 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=365936\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Eight people are going to line up to get on a bus. <BR>\n" );
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document.write( "Three of those people are husband, wife and their daughter that must follow each other when they line up to get on the bus. <BR>\n" );
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document.write( "How many ways are possible for the line up?<BR>\n" );
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document.write( "Treat the 3 family members as a unit that can be arranged 3! = 6 ways<BR>\n" );
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document.write( "Then you have 5 individual plus the family to arrange is 6! = 720 ways<BR>\n" );
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document.write( "Total # of arrangements: 6*720 = 4320<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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