document.write( "Question 565690: Solve,\r
\n" ); document.write( "\n" ); document.write( "x + y = 6
\n" ); document.write( "y = 2x - 3\r
\n" ); document.write( "\n" ); document.write( "I'm completely lost\r
\n" ); document.write( "\n" ); document.write( "Daren \n" ); document.write( "
Algebra.Com's Answer #365935 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Let's see if we can find you.
\n" ); document.write( ":
\n" ); document.write( "Solve,
\n" ); document.write( "x + y = 6
\n" ); document.write( "y = 2x - 3
\n" ); document.write( ":
\n" ); document.write( "Note that the 2nd equation tell us y = (2x-3)
\n" ); document.write( "so replace y with (2x-3) in the 1st equation
\n" ); document.write( "x + (2x-3) = 6
\n" ); document.write( "3x - 3 = 6
\n" ); document.write( "add 3 to both sides
\n" ); document.write( "3x = 6 + 3
\n" ); document.write( "3x = 9
\n" ); document.write( "x = 9/3
\n" ); document.write( "x = 3
\n" ); document.write( ":
\n" ); document.write( "Find y using y = 2x - 3, replace x with 3, and you have
\n" ); document.write( "y = 2(3) - 3
\n" ); document.write( "y = 6 - 3
\n" ); document.write( "y = 3
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "We can check our solutions of x=3, y=3 in the 1st equation x + y = 6
\n" ); document.write( "3 + 3 = 6. You can check in the 2nd equation
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